3c^2-17c-6=0

Solution for 3c^2-17c-6=0 equation:

Simplifying
3c2 + -17c + -6 = 0

Reorder the terms:
-6 + -17c + 3c2 = 0

Solving
-6 + -17c + 3c2 = 0

Solving for variable 'c'.

Factor a trinomial.
(-1 + -3c)(6 + -1c) = 0

Subproblem 1
Set the factor '(-1 + -3c)' equal to zero and attempt to solve:

Simplifying
-1 + -3c = 0

Solving
-1 + -3c = 0

Move all terms containing c to the left, all other terms to the right.

Add '1' to each side of the equation.
-1 + 1 + -3c = 0 + 1

Combine like terms: -1 + 1 = 0
0 + -3c = 0 + 1
-3c = 0 + 1

Combine like terms: 0 + 1 = 1
-3c = 1

Divide each side by '-3'.
c = -0.3333333333

Simplifying
c = -0.3333333333
Subproblem 2
Set the factor '(6 + -1c)' equal to zero and attempt to solve:

Simplifying
6 + -1c = 0

Solving
6 + -1c = 0

Move all terms containing c to the left, all other terms to the right.

Add '-6' to each side of the equation.
6 + -6 + -1c = 0 + -6

Combine like terms: 6 + -6 = 0
0 + -1c = 0 + -6
-1c = 0 + -6

Combine like terms: 0 + -6 = -6
-1c = -6

Divide each side by '-1'.
c = 6

Simplifying
c = 6
Solution
c = {-0.3333333333, 6}